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30q^2+19q-4=0
a = 30; b = 19; c = -4;
Δ = b2-4ac
Δ = 192-4·30·(-4)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-29}{2*30}=\frac{-48}{60} =-4/5 $$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+29}{2*30}=\frac{10}{60} =1/6 $
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